这是第2套题中的51-90题
310-025
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Question No 51
Exhibit:
1. import java.io.IOException;
2. public class ExceptionTest(
3. public static void main (String[]args)
4. try (
5. methodA();
6. ) catch (IOException e) (
7. system.out.printIn(“Caught IOException”);
8. ) catch (Exception e) (
9. system.out.printIn(“Caught Exception”);
10. )
11. )
12. public void methodA () {
13. throw new IOException ();
14. )
15. )
What is the result?
A. The code will not compile.
B. The output is caught exception.
C. The output is caught IOException.
D. The program executes normally without printing a message.
Answer: A
Question No 52
Exhibit:
1. public class test {
2. public static string output = “”
3.
4. public static void foo(int i) {
5. try {
6. if(i= =1) {
7. throw new Exception ();
8. }
9. output += “1”;
10. )
11. catch(Exception e) {
12. output += “2”;
13. return;
14. )
15. finally (
16. output += “3”;
17. )
18. output += “4”;
19. )
20.
21. public static void main (string args[]) (
22. foo(0);
23. foo(1);
24.
25. )
26. )
What is the value of the variable output at line 24?
Answer: 13423
Question No 53
Given:
1. public class Foo implements Runnable (
2. public void run (Thread t) {
3. system.out.printIn(“Running.”);
4. }
5. public static void main (String[] args) {
6. new thread (new Foo()).start();
7. )
8. )
What is the result?
A. An exception is thrown.
B. The program exists without printing anything.
C. An error at line 1 causes compilation to fail.
D. An error at line 2 causes the compilation to fail.
E. “Running” is printed and the program exits.
Answer: D
Question No 54
Which statement is true?
A. If only one thread is blocked in the wait method of an object, and another thread executes the
modify on that same object, then the first thread immediately resumes execution.
B. If a thread is blocked in the wait method of an object, and another thread executes the notify
method on the same object, it is still possible that the first thread might never resume execution.
C. If a thread is blocked in the wait method of an object, and another thread executes the notify
method on the same object, then the first thread definitely resumes execution as a direct and sole
consequence of the notify call.
D. If two threads are blocked in the wait method of one object, and another thread executes the notify
method on the same object, then the first thread that executed the wait call first definitely resumes
execution as a direct and sole consequence of the notify call.
Answer: B
Question No 55
Which two CANNOT directly cause a thread to stop executing? (Choose Two)
A. Calling the yield method.
B. Calling the wait method on an object.
C. Calling the notify method on an object.
D. Calling the notifyAll method on an object.
E. Calling the start method on another Thread object.
Answer: C, D
Question No 56
Which two can be used to create a new Thread? (Choose Two)
A. Extend java.lang.Thread and override the run method.
B. Extend java.lang.Runnable and override the start method.
C. Implement java.lang.thread and implement the run method.
D. Implement java.lang.Runnable and implement the run method.
E. Implement java.lang.Thread and implement the start method.
Answer: A, D

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